Find a three digit number, knowing that the sum of the first two digits is 13 , the difference of the last two is 1 and the sum of all three digits is 16
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Find a three digit number, knowing that the sum of the first two digits is 12, the difference of the last two is 3 and the sum of all three digits is 18.
We note: with a - the first digit, b - the second digit, c - the third digit
Because
a + b + c = 18
a + b = 12
We will calculate the third digit which is equal to the difference of the two sums
c = 18 - 12
c = 6
Knowing the last digit and that the difference of the first two digits is 3 , the second digit is going to be
b = c + 3
b = 9
We calculate the last digit by subtracting from the given sum the two known digits
18 - c - b
18 - 6 - 9 = 3
a = 3
We will write the number
abc
396
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